![]() ![]() In this solution, we iterate over the array and build the map which stores array elements and their count. This is a pretty good solution because you can extend it to the found count of duplicates as well. Our third solution to find duplicate elements in an array is actually similar to our second solution but instead of using a Set data structure, we will use the hash table data structure. This solution has a time complexity of O(n), as you only need to iterate over array once, but also has a space complexity of O(n) as you need to store unique elements in the array. You can take advantage of this property to filter duplicate elements. If you remember, Set abstract data type doesn't allow duplicates. ![]() The standard way to find duplicate elements from an array is by using the HashSet data structure. You shouldn't be using this solution in the real world. This solution has the time complexity of O(n^2) and only exists for academic purposes. One of the most common ways to find duplicates is by using the brute force method, which compares each element of the array to every other element. String array or integer array or array of any object. The solution and logic shown in this article are generic and apply to an array of any type e.g. There are multiple ways to find duplicate elements in an array in Java and we will see three of them in this program. ![]()
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